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It is easy to charge a capacitor, and then to pump that charge into another capacitor.
- The top capacitor normally wants to charge. A diode is needed though, so the capacitor will stop charging when it is a diode drop below the supply voltage. The lower capacitor will also get charged if it is below 2 diode drops less than the supply voltage.
- Closing the switch will put the positive supply in series with the top capacitor. That will push current through the other diode and into the lower capacitor. The top capacitor’s voltage will be added to the supply voltage as far as the lower capacitor is concerned. There will be the diode drop though, since current has to flow through the diode.
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