Monostable 555 timer has a low output unless it is forced to go high for a period of time. The output however returns to low when that time period is over. It stays low as long as it is left alone. Monostable means that there is one stable state, which is low.
- Pin 4 (reset) is connected to the positive supply to prevent pin 4 from setting the output low. A low (close to 0V/ground) signal to pin 4 will make it so the output is low, no matter what else is going on.
- A low input to pin 2 (trigger) will set the output high, and start charging the timing capacitor through the timing resistor.
- Once pin 6 (threshold) senses that the capacitor has charged to 2/3 of the supply voltage (2/3 of 5V in this case), then the output goes low, and the capacitor instantly discharges through pin 7 (discharge).
- LED between +5V and output lights up when the output is low. As that is when there is a voltage difference across the LED and it’s protective resistor. I usually use a blue LED, to indicate a low output.
- On the other hand, the LED between the output and ground (0V) lights up when the output is high. There will be close to 4V at the output when it is high, some voltage is lost due to the transistors used in most 555 timers. I usueally use a red LED to indicate that the output is high.
To support this site, check out the following links:
- Check out my YouTube videos! https://www.youtube.com/c/Electronzap/videos
- Products I used in my videos or otherwise think look like a good buy. As an Amazon associate, I earn from qualifying purchases. https://www.amazon.com/shop/electronzapdotcom
- Information on this site is not guaranteed to be accurate. Always consult the manufacturer info/datasheet of parts you use. Research the proper safety precautions for everything you do.
- Electronzap is a participant in the Amazon Services LLC Associates Program, an affiliate advertising program designed to provide a means for sites to earn advertising fees by advertising and linking to amazon.com.